Is there a way to get syslog to report the time in 12 hr format?
Thanks.
Is there a way to get syslog to report the time in 12 hr format?
Thanks.
@tkn is the Syslog time controlled by the clock settings? I've never used Syslog. Changed clock to 12hr and still showing 24hr in syslog.
I got the same thing. It still shows 24 hr format?
I would think the predefined format isn't set up for A.M. P.M. in the syslog.
Here is a link maybe you can explore:
oops.... my fault. I overlooked the word 'syslog'
No, there is no such option.
All systemlogging is done by journald in the background an stored in binary format.
To read the logs we use journalctl which actually has some display options.
The time formatting options are limited (either locale-dependent, but still 24-hour, or Unix timestamps, or ISO 8601 timestamps).
So no, unless you create a little script to convert the output of journalctl you're stuck
I have a little script here that will display the log output in 12h timeformat:
#!/bin/bash
journalctl | while read line
do
case "${line:7:1}" in
0 ) hour="${line:8:1}" ;;
1|2) hour="${line:7:2}" ;;
* ) echo "$line" ; continue ;;
esac
(( hour > 12 )) && ampm=pm && (( hour -= 12 )) || ampm=am
printf "%s%s %02d%s\n" "${line:0:7}" "$ampm" "$hour" "${line:9}"
done
EDIT: fixed a small bug
Thanks a lot tkn.
Andy